AB Control Logix 5000 Hw 1756, 5556 Logix Control Net New project On left I O Configuration right click to add modules Check firmware no. I.e. 2.5 on side of module, and model no. While adding v hav to enter it On left Task->Main Task->Main Program-> Main Routine double click e e e e beside Rungs means Error in rung will appear if Elements like PB coil not assigned addresses. To assign addr right click on element Alias Local1:Idata0 (its on main Shaashi Local PLC not Remote) I input, 0 first bit. After assigning it will apear in Controller Tags Folder on Left of main screen. After No Error Save program Open RS linx RS232 communication, ->Configure Driver-> choose in Available Drivers-> AB DF1 RS232 Devices-> Com Port, Baud Rate, Parity etc will b asked Just set right Port n press AUTO CONFIGURE. It will show successful. Close it then u will see in Configure driver window its in Running status. Click OK Go to top menu Communication->WHO ACTIVE select...
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1: Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 Answers: i. 135 and 225 As you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have, 225 = 135 × 1 + 90 Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get, 135 = 90 × 1 + 45 Again, 45 ≠ 0, repeating the above step for 45, we get, 90 = 45 × 2 + 0 The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45. Hence, the HCF of 225 and 135 is 45. ii. 196 and 38220 In this given question, 38220>196, therefore the by applying Euclid’s division algorithm and taking 38220 as divisor, we get, 38220 = 196 × 195 + 0 We have already got the remainder as 0 here. Therefore, HCF(196, 38220) = 196. Hence, the HCF of 196 and 38220 is 196. iii. 867 and 225 As we know, 867 is greater ...